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- Thread starter GeolPhysics
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- #2

DrClaude

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- #3

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Yeah, it's the appearance of ##(i/\hbar)^2##

- #4

DrClaude

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$$

\frac{\partial^2}{\partial x^2} e^{ax} = a^2 e^{ax}

$$

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I only managed to get this. Can you show me the exact steps on how you ended up with the second line?

$$

\frac{\partial^2}{\partial x^2} e^{ax} = a^2 e^{ax}

$$

- #6

Nugatory

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Did you intend to ask what ##e## is? It’s Euler’s number, and ##exp(a)## is another notation for ##e^a##. If you not already familiar with its properties you’re going to have to put some time into first-year differential and integral calculus before you can take on Schrodinger’s equation.And what are the values of a, e and x?

If that was just a slip of the typing fingers, go back to the ##\psi## suggested in the text, then rewrite the exponential of sums as a product of exponentials. Now you’ll be able to take the second derivative with respect to ##x## to get the ##(i/\hbar)^2## factor.

- #7

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