Analyzing the global flood from a perspective of math
I figured that I would take a purely objective and mathematical look at the statement of the Noacian Delugue (the Great Flood). Not starting from any supposition of right or wrong on the story, I simply wished to check the forces at work in our flood story. I'm not even concerned with the feasability of collecting animals or fiting them in a boat, just the natural forces described. So here's the process.
1) Given: The stated flood covered all land on earth.
2) Given: the duration of the flood is stated at 40 24-hour periods.
3) To determine the amount of water needed for this flood...
radius of Earth = 6,367,443 M
Highest Point: Mount Everest = 8,850 M
Volume of the earth = 1,081,393,630,274,105,660,580.262 m^3 = 1.081*10^21 m^3 = 1.081*10^24 L
Volume of the earth+Mount Everest = 1,085,908,931,675,316,662,626.475 = 1.085*10^21 m^3 = 1.085*10^24 L
Volume of water to cover all land on earth approx. = 4,515,301,401,211,002,046.213 m^3 = 4.515*10^18 m^3 = 4.515*10^21 L
Well, that's a really big number, but the earth is pretty big as well, so lets get some more data.
4)To determine the force of the rain, I must first discover the rate of the rainfall.
Given duration of rainfall = 40d = 960 h = 57,600 min = 3,456,000 s
Rate of rainfall needed to fill volume of water to peak of Everest = 4,515,301,401,211,002,046,213 L / 3,456,000s = 1,306,510,822,109,664.944 L/s = 1.307*10^15 L/s
Once again, large large numbers, but this is still planetary scale.
5)Averaging for an even rainfall...
Surface area of earth = 510,065,600 Km^2
Rainfall rate per km^2 = 2,561,456.452 L/s per Km^2 = 2.561 L/s per m^2
Now that we have the amount of rain falling at a given rate at a workable area on human scale we can get the force of the rain.
6)Force of the rainfall per square meter
1L water = 1kg
Mass hitting the ground for every m^2 = 2.561 kg/s
Average raindrop velocity between 2m/s and 9m/s = 5.5 m/s (source http://www.wonderquest.com/falling-raindrops.htm)
Kinetic energy (E=.5mv^2) of rain hitting the earth every second = .5*2.56kg1*5.5m/s^2 = 38.753 N = 8.712lbs
A continuous 38.753 Newtons on every square meter of earth for 40 days is not rain, it is the equivalence of hydrological stripmining. With this much water, you would not end up with canyons and rifts, you would end up with everything not made of bedrock being eroded into the lowest basin zones on the earth. No topsoil would remain, no sandstone or limestone, granite formations would break apart at stress seams. You are also looking at a rise in water level by around 2.56 cm per second (1 inch per second). Any thing floating on top of this water would be pushed up into the rain, effectively increasing the force with which the rain hits the object by around a factor of 2.
Given that I'm no geologist or mechanical engineer, I'm not sure of the effects on surface tension from this much rain, or currents and water turbulance. However, by my findings here I conclude that we should have none of the land masses we now know given a global flood of this magnitude.
If anyone wishes to check my math, please do so. Also if there are any engineers that can give a better understanding of what 38.753 N per second for 40 days would imply mechanically, I'd love to know.
The Regular Expressions of Humanistic Jones: Where one software Engineer will show the world that God is nothing more than an undefined pointer.